w^2-4w+17=3

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Solution for w^2-4w+17=3 equation: 



w^2-4w+17=3

We move all terms to the left:

w^2-4w+17-(3)=0

We add all the numbers together, and all the variables

w^2-4w+14=0

a = 1; b = -4; c = +14;
Δ = b2-4ac
Δ = -42-4·1·14
Δ = -40
Delta is less than zero, so there is no solution for the equation

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